4m^2=9-9m

Solution for 4m^2=9-9m equation:

4m^2=9-9m

We move all terms to the left:

4m^2-(9-9m)=0

We add all the numbers together, and all the variables

4m^2-(-9m+9)=0

We get rid of parentheses

4m^2+9m-9=0

a = 4; b = 9; c = -9;
Δ = b2-4ac
Δ = 92-4·4·(-9)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*4}=\frac{-24}{8}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*4}=\frac{6}{8}
=3/4
$